How can I convert this to preg_replace?

$TEMPLATE_PATH = ereg_replace("(/)+" ,"/",$TEMPLATE_PATH);

 

Thanks!

The regex uses / as the delimiter when searching for / you escape it like so \/ see example test code

 

<?php
$TEMPLATE_PATH ="c://test//example/////test.php";
print $TEMPLATE_PATH;
$TEMPLATE_PATH = ereg_replace("(/)+" ,"/",$TEMPLATE_PATH);	  //----Deprecated
$TEMPLATE_PATH = preg_replace('/(\/)+/', '/', $TEMPLATE_PATH);
print $TEMPLATE_PATH;
?>

Thank you very much!

Almost finished the fix for php 5.3

But stuck with this "Easy-to-Read" code

 

  $REP_UNDSCR="&| ";
 $REP_SPACE="\?|%|'|\"|'|%|/|\||"|\*|#|\^|{|}|;|!|:|~|`|<|>|<|>|,|\\|\(|\)";
 $ADDITIONAL_VAL = ereg_replace($REP_UNDSCR,'_',$ADDITIONAL_VAL);
 $ADDITIONAL_VAL = ereg_replace($REP_SPACE,'',$ADDITIONAL_VAL);

 

Someone can help to convert this to preg_replace